2025 May 22nd EAPCET Engineering Forenoon Practice Test

Test Description

This EAPCET Engineering Practice Test was a previous year EAPCET exam conducted on 2025 May 22nd shift 1. This test consists of 160 objective type questions from both Intermediate First Year and Intermediate Second Year Mathematics (80), Physics (40) and Chemistry (40). The questions are given in the same format as in the exam conducted by Andhra Pradesh (AP) EAPCET exam in the year 2025.

This test is completely free, and students can attempt as many times as needed and help students in preparing for EAPCET entrance tests and get admissions into various reputed colleges for Engineering in the state of Andhra Pradesh.

Test Instructions

The test contains 160 multiple-choice questions.
Total time for the test is 3h 00m.
Each question carries equal marks.
There is no negative marking for wrong answers.
Use of calculator is not allowed.
Do not refresh the page during the test.
Make sure you have a stable internet connection.

Quick Test

(1 of 160) Let

f : N \to N

be a function such that

f (x + y) = f (x) + f (y) + xy

for every

x, y \in N

. If

f (1) = 2

, then

\sum_{k = 0}^{10} f (k) =

1650
275
550
1025

(2 of 160) If a real valued function

f : [- 1, 2] \to B

defined by

f (x) = \{\begin{cases} 1 - x, & when - 1 \leq x \leq 1 \\ x - 1, & when 1 \leq x \leq 2 \end{cases}

is a surjection, then B=

[-1, 2]
[-1, 1]
[0, 2]
[0, 1]

(3 of 160) For all

n \in N, \frac{3^{n} - 1}{2} \geq

$n^{2} (2^{n / 2})$
$n^{2} (3^{\frac{n - 1}{2}})$
$n^{3} (3^{\frac{n - 1}{2}})$
$n (3^{\frac{n - 1}{2}})$

(4 of 160) The values of p and q so that the system of equations 2x+py+6z=8, x+2y+qz=5 and x+y+3z=4 may have no solution are

$p \neq 2, q = 3$
$p \neq 2, q \neq 3$
$p = 2, q = \frac{15}{4}$
$p = 2, q = 3$

(5 of 160) A is the set of all matrices of order 3 with entries 0 or 1 only. B is the subset of A consisting of all matrices with determinant value 1. If C is the subset of A consisting of all matrices with determinant value -1, then

$A = B \cup C$
C is empty
B and C contain the same number of elements
B has twice as many elements as C

(6 of 160) Consider the matrices

A = [\begin{matrix} x & y & 0 \\ - 3 & 1 & 2 \\ 1 & - 2 & z \end{matrix}] and B = [\begin{matrix} 1 & - 2 & - 2 \\ 2 & 0 & 1 \\ 2 & 1 & 0 \end{matrix}]

If the cofactors of the elements z, 1 in 3rd row and x of A are 9, 4, 3 respectively then AB=

$[\begin{matrix} - 7 & - 4 & - 8 \\ - 1 & 8 & 7 \\ 3 & - 3 & - 4 \end{matrix}]$
$[\begin{matrix} 7 & - 6 & 8 \\ - 5 & 4 & - 5 \\ - 5 & - 3 & - 4 \end{matrix}]$
$[\begin{matrix} 7 & - 6 & - 4 \\ 3 & 8 & 7 \\ - 5 & - 3 & - 4 \end{matrix}]$
$[\begin{matrix} 7 & - 6 & 8 \\ - 1 & 8 & - 5 \\ 3 & - 3 & - 4 \end{matrix}]$

(7 of 160) The minimum value of |z-1|+|z-5| is

(8 of 160) If z=x+iy and if the point P in the Argand diagram represents z, then the locus of the point P satisfying the equation 2|z-2-3i|=3|z+i-2| is a circle with centre