2025 May 21st EAPCET Engineering Afternoon Practice Test

Test Description

This EAPCET Engineering Practice Test was a previous year EAPCET exam conducted on 2025 May 21st shift 2. This test consists of 160 objective type questions from both Intermediate First Year and Intermediate Second Year Mathematics (80), Physics (40) and Chemistry (40). The questions are given in the same format as in the exam conducted by Andhra Pradesh (AP) EAPCET exam in the year 2025.

This test is completely free, and students can attempt as many times as needed and help students in preparing for EAPCET entrance tests and get admissions into various reputed colleges for Engineering in the state of Andhra Pradesh.

Test Instructions

The test contains 160 multiple-choice questions.
Total time for the test is 3h 00m.
Each question carries equal marks.
There is no negative marking for wrong answers.
Use of calculator is not allowed.
Do not refresh the page during the test.
Make sure you have a stable internet connection.

Quick Test

(1 of 160) The set of all real values of X such that

f (x) = \sqrt{\frac{[x] - 1}{{[x]}^{2} - [x] - 6}}

is a real valued function is

$[1, \infty)$
$(- \infty, - 2) \cup [4, \infty)$
$[- 1, 3)$
$[- 1, 2) \cup [4, \infty)$

(2 of 160) If a function

f : Z \to Z

is defined by

f (x) = x - {(- 1)}^{x}

, then

f (x)

one-one, but not onto
onto, but not one-one
both one-one and onto
neither one-one nor onto

(3 of 160) If 2.5 + 5.9 + 8.13 + 11.17 + ..... to n terms

= a n^{3} + b n^{2} + c n + d

, then a-b+c-d=

7
5
-3
-1

(4 of 160) If

A = [\begin{matrix} 1 & 2 & - 2 \\ 2 & - 1 & 2 \\ - 1 & 1 & - 2 \end{matrix}]

, then

A + 2 A^{- 1} =

$[\begin{matrix} 1 & 4 & 0 \\ 4 & - 5 & - 4 \\ 0 & - 2 & - 7 \end{matrix}]$
$[\begin{matrix} 0 & 2 & 2 \\ 2 & - 4 & - 6 \\ 2 & - 3 & - 5 \end{matrix}]$
$[\begin{matrix} 0 & 2 & 1 \\ 2 & - 4 & - 3 \\ 2 & - 6 & - 5 \end{matrix}]$
$[\begin{matrix} 1 & 4 & - 1 \\ 4 & - 5 & - 1 \\ 1 & - 5 & - 7 \end{matrix}]$

(5 of 160) If

A = [\begin{matrix} a & b & c \\ d & e & f \\ l & m & n \end{matrix}]

is matrix such that

|A| > 0

and

A d j A = [\begin{matrix} 0 & 4 & - 6 \\ 10 & 8 & 0 \\ 2 & 4 & - 4 \end{matrix}]

, then

\frac{c d}{f b} + \frac{\ln}{e m} =

$2 a$
$a + m$
$a + b$
$a$

(6 of 160) In solving a system of linear equations AX=B by Cramer's rule, in the usual notation, if

Δ_{1} = |\begin{matrix} - 11 & 1 & - 7 \\ - 4 & 1 & - 2 \\ 5 & 1 & 1 \end{matrix}|

and

Δ_{3} = |\begin{matrix} 4 & 1 & - 11 \\ 1 & 1 & - 4 \\ 4 & 1 & 5 \end{matrix}|

, then X=

$[\begin{matrix} - 1 \\ 1 \\ 2 \end{matrix}]$
$[\begin{matrix} 2 \\ 1 \\ - 1 \end{matrix}]$
$[\begin{matrix} 1 \\ - 1 \\ 2 \end{matrix}]$
$[\begin{matrix} 1 \\ 2 \\ - 1 \end{matrix}]$

(7 of 160) If

a = I m (\frac{1 + z^{2}}{2 i z})

and z is any non zero complex number such that

|z| = 1

, then a=

Re(Z)
Re(Z) Im(Z)
-Re(Z)
Re(Z)+Im(Z)

(8 of 160) If

{(3 + 4 i)}^{2025} = 5^{2023} (x + i y)

, then

\sqrt{x^{2} + y^{2}} =

(9 of 160) If

{(\frac{\cos θ + i s i n θ}{\sin θ + i c o s θ})}^{2024} + {(\frac{1 + c o s θ + i s i n θ}{1 - c o s θ + i s i n θ})}^{2025} = x + i y

, then the value of

x + y

θ = \frac{π}{2}

1
-1
2
2024

(10 of 160) The roots

α, β

of the equation

x^{2} - 6 (k - 1) x + 4 (k - 2) = 0

are equal in magnitude but opposite in sign. If

α > β

, then the product of the roots of the equation

2 x^{2} - α x + 6 β (α + 1) = 0

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Test Details

Duration

3h 00m

Questions

160 Multiple Choice Questions

Passing Score

N/A% or higher to pass

Attempts

Unlimited attempts allowed

Total Runs

100

Test Description

Test Instructions

Quick Test

Practice Tests

Test Details

Duration

Questions

Passing Score

Attempts

Total Runs

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