EAMCET Mathematics Practice Test 019

Test Description

This Mathematics Practice Test is the ninteenth mock test in the series of many Mathematics tests. This test consists of 40 objective type questions from both Intermediate First Year and Intermediate Second Year Mathematics. This test provides questions in the format of Andhra Pradesh (AP) EAPCET and Telangana (TS) EAMCET.

This test is completely free, and students can attempt as many times as needed and help students in preparing for entrance tests and get admissions into various reputed colleges for Engineering.

Test Instructions

The test contains 40 multiple-choice questions.
Total time for the test is 0h 45m.
Each question carries equal marks.
There is no negative marking for wrong answers.
Use of calculator is not allowed.
Do not refresh the page during the test.
Make sure you have a stable internet connection.

Quick Test

(1 of 40) The range of 'a' so that

a^{2} x^{2} + 2 x y + 4 y^{2} = 0

represents two distinct lines is

$a > \frac{1}{2} or a < \frac{- 1}{2}$
$\frac{- 1}{2} \leq a \leq \frac{1}{2}$
$\frac{- 1}{2} < a < \frac{1}{2}$
$a \geq \frac{1}{2} or a \leq \frac{- 1}{2}$

(2 of 40) If a diameter of the circle

x^{2} + y^{2} - 4 x + 6 y - 12 = 0

is a chord of a circle S whose centre is at (-3,2), then the radius of S is

$5 \sqrt{3}$
$4 \sqrt{3}$
$2 \sqrt{3}$
5

(3 of 40) If a circle passing through A(1,1) touches the X-axis, then the locus of the other end of the diameter through A is

${(x + 1)}^{2} = 4 y$
${(y - 1)}^{2} = 4 x$
${(x - 1)}^{2} = 4 y$
${(y + 1)}^{2} = 4 x$

(4 of 40) If two circles

x^{2} + y^{2} - 6 x - 6 y + 13 = 0

and

x^{2} + y^{2} - 8 y + 9 = 0

intersect at A and B, then the focus of the parabola whose directrix is the line AB and vertex is the point O(0,0) is

$(\frac{3}{5}, \frac{1}{5})$
$(- \frac{3}{5}, \frac{1}{5})$
$(- \frac{3}{5}, - \frac{1}{5})$
$(\frac{3}{5}, - \frac{1}{5})$

(5 of 40) A particle is travelling in clockwise direction on the ellipse

\frac{x^{2}}{100} + \frac{y^{2}}{25} = 1

. If the particle leaves the ellipse at the point (-8,3) on it and travels along the tangent to the ellipse at that point then the point where the particle crosses the Y-axis is

$(0, \frac{7}{3})$
$(0, \frac{25}{3})$
(0,9)
$(0, \frac{- 25}{3})$

(6 of 40) If the equation of a hyperbola is

9 x^{2} - 16 y^{2} + 72 x - 32 y - 16 = 0

, then the equation of its conjugate hyperbola is

$9 x^{2} - 16 y^{2} + 72 x - 32 y + 272 = 0$
$9 x^{2} - 16 y^{2} + 72 x - 32 y + 288 = 0$
$9 x^{2} - 16 y^{2} + 72 x - 32 y - 38 = 0$
$9 x^{2} - 16 y^{2} + 72 x - 32 y + 16 = 0$

(7 of 40) If the direction cosines (l, m, n) of two lines are connected by the relations l+m+n=0 and lm=0, then the angle between those lines is

$\frac{π}{3}$
$\frac{π}{4}$
$\frac{π}{2}$
$\frac{π}{6}$

(8 of 40) The sum of the squares of the perpendicular distances of a point (x, y, z) from the coordinate axes is k times the square of the distance of the point from the origin. Then k=

(9 of 40) Equation of the plane through the mid-point of the line segment joining the points A (4,5,-10) and B (-1,2,1) and perpendicular to AB is

10x+6y-22z+135=0
10x+6y-22z-135=0
5x+3y+11z=135
10x+6y-22z+185=0

(10 of 40)

\lim_{x \to 1} \frac{(2 x - 3) (\sqrt{x} - 1)}{2 x^{2} + x - 3} =

$\frac{1}{10}$
$- \frac{1}{10}$
$\frac{2}{5}$
$- \frac{2}{5}$

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Test Details

Duration

0h 45m

Questions

40 Multiple Choice Questions

Passing Score

N/A% or higher to pass

Attempts

Unlimited attempts allowed

Total Runs

100