EAMCET Mathematics Practice Test 003

Test Description

This Mathematics Practice Test is the third mock test in the series of many Mathematics tests. This test consists of 40 objective type questions from both Intermediate First Year and Intermediate Second Year Mathematics. This test provides questions in the format of Andhra Pradesh (AP) EAPCET and Telangana (TS) EAMCET.

This test is completely free, and students can attempt as many times as needed and help students in preparing for entrance tests and get admissions into various reputed colleges for Engineering.

Test Instructions

The test contains 40 multiple-choice questions.
Total time for the test is 0h 45m.
Each question carries equal marks.
There is no negative marking for wrong answers.
Use of calculator is not allowed.
Do not refresh the page during the test.
Make sure you have a stable internet connection.

Quick Test

(1 of 40) If

{(3 + 2 \sqrt{2})}^{x^{2} - 4} + {(3 - 2 \sqrt{2})}^{x^{2} - 4} = 6

, then

x^{4} + x^{2} + 5 =

(2 of 40) If the equation

x^{4} + {ax}^{3} + {bx}^{2} + cx + d = 0

has three equal roots, then that root is

$\frac{6 c - ab}{8 b - 3 a^{2}}$
$\frac{ab - 6 c}{8 b + 3 a^{2}}$
$\frac{6 c - ab}{3 a^{2} - 4 b}$
$\frac{6 c - ab}{3 a^{2} - 8 b}$

(3 of 40) If -1 is a twice repeated root of the equation

a (x^{3} + x^{2}) + bx + c = 0

, then

a : b : c =

-1:1
-1:1:1
1:1:-1
1:1:1

(4 of 40) If the number of diagonals of a regular polygon of n sides is 104, then n=

(5 of 40) If

{(2 - 5 x)}^{\frac{- 1}{5}} = a_{0} + a_{1} x + a_{2} x^{2} + . . . .,

then

\frac{a_{1}}{a_{2}} =

$\frac{1}{3}$
$- \frac{2}{3}$
$- \frac{1}{3}$
$\frac{2}{3}$

(6 of 40) The number of natural numbers less than 10000 which are divisible by 5 and that no digit is repeated in the same number, is

802
602
702
1106

(7 of 40) A team of 5 students is to be selected from 12 students. If two particular students are to be included in that team, then the number of ways that such team can be selected is

(8 of 40)

\sin 21 ° \cos 9 ° - \cos 84 ° \cos 6 ° =

1
$\frac{1}{4}$
$\frac{1}{2}$
$\frac{3}{2}$

(9 of 40)

\frac{1}{\cos 290 °} + \frac{1}{\sqrt{3} \sin 250 °} =

$\frac{\sqrt{3}}{4}$
$\frac{4}{\sqrt{3}}$
$\frac{2}{\sqrt{3}}$
$\frac{\sqrt{3}}{2}$

(10 of 40) If

{[1 - \cos (\frac{π}{2} + α) + \sin (\frac{3 π}{2} + α)]}^{2} + {[1 - \sin (\frac{3 π}{2} - α) - \cos (\frac{3 π}{2} + α)]}^{2}

= a + b \sin^{2} (\frac{π}{4} + α)

, then

a^{2} + b^{2} =

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Test Details

Duration

0h 45m

Questions

40 Multiple Choice Questions

Passing Score

N/A% or higher to pass

Attempts

Unlimited attempts allowed

Total Runs

100

Test Description

Test Instructions

Quick Test

Practice Tests

Test Details

Duration

Questions

Passing Score

Attempts

Total Runs

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