EAMCET Mathematics Practice Test 002

Test Description

This Mathematics Practice Test is the second mock test in the series of many Mathematics tests. This test consists of 40 objective type questions from both Intermediate First Year and Intermediate Second Year Mathematics. This test provides questions in the format of Andhra Pradesh (AP) EAPCET and Telangana (TS) EAMCET.

This test is completely free, and students can attempt as many times as needed and help students in preparing for entrance tests and get admissions into various reputed colleges for Engineering.

Test Instructions

The test contains 40 multiple-choice questions.
Total time for the test is 0h 45m.
Each question carries equal marks.
There is no negative marking for wrong answers.
Use of calculator is not allowed.
Do not refresh the page during the test.
Make sure you have a stable internet connection.

Quick Test

(1 of 40) The locus of a point which is at a distance of 2 units from the line

2 x - 3 y + 4 = 0

and at a distance of

\sqrt{13}

units from a point

(5, 0)

, is

$8 x^{2} + 12 xy + 56 x - 24 y + 84 = 0$
$12 xy - 5 y^{2} - 56 x + 24 y + 84 = 0$
$8 x^{2} + 12 xy + y^{2} - 56 x + 24 y + 84 = 0$
$8 x^{2} + 12 xy - 7 y^{2} - 56 x + 24 y + 84 = 0$

(2 of 40) The combined equation of the lines passing through the point (3,4) and each making an angle

45 °

with the line

x + y + 1 = 0

$xy - 4 x - 3 y + 12 = 0$
$(3 x - 2 y - 1) (x - 2 y + 2) = 0$
$(3 x + 2 y - 17) (x + 2 y - 11) = 0$
$xy - 4 x + 3 y + 12 = 0$

(3 of 40) The equal sides of an isosceles triangle are given by equations

7 x - y + 3 = 0

and

x + y - 3 = 0

. If the slope m of the third side is an integer, then m=

-3
3
4
-1

(4 of 40) In

∆ ABC

the coordinates of the vertex A are (-3,1). If the equation of median through B is

2 x + y - 3 = 0

and the equation of the bisector of angle C is

7 x - 4 y - 1 = 0

, then the equation of the side BC is

$7 x - 3 y = 6$
$18 x - y = 49$
$15 x + y = 50$
$4 x - y = 7$

(5 of 40) If the lines given by

(x^{2} + y^{2}) \sin^{2} α = {(x \cos α - y \sin α)}^{2}

are perpendicular to each other, then

\sin^{2} α + \tan^{2} α =

$\frac{15}{4}$
$0$
$\frac{3}{2}$
$\frac{7}{12}$

(6 of 40) If the area of the triangle formed by the lines

y = x + c

and

2 x^{2} + 5 xy + 3 y^{2} = 0

\frac{1}{20}

sq. units, then c=

$\pm 1$
$\pm \sqrt{2}$
$\pm 3$
$\pm \sqrt{3}$

(7 of 40) If the line passing through the points (5,1, a) and (3, b,1) crosses the YZ plane at the point

(0, \frac{17}{2}, \frac{- 13}{2})

, then

a + b =

(8 of 40)

∆ ABC

is formed by A(1,8,4), B(0,-11,4) and C(2,-3,1). If D is the foot of the perpendicular drawn from A to BC, then the coordinates of D are

(-4,5,2)
(4,-5,2)
(4,-5,-2)
(4,5,-2)

(9 of 40) The distance between two parallel planes

ax + by + cz + d_{1} = 0

ax + by + cz + d_{2} = 0

is given by

\frac{|d_{1} - d_{2}|}{\sqrt{a^{2} + b^{2} + c^{2}}}

. If the plane

2 x - y + 2 z + 3 = 0

has the distances

\frac{1}{3}

and

\frac{2}{3}

units from the planes

4 x - 2 y + 4 z + λ = 0

and

2 x - y + 2 z + μ = 0

respectively, then the maximum value of

λ + μ

(10 of 40) Let S be the circumcircle of the triangle formed by the line x-2y-4=0 with the coordinate axes. If P (-2,-4) is a point in the plane of the circle S and Q is a point on S such that the distance between P and Q is the least, then PQ=

$5 - \sqrt{5}$
$5 + \sqrt{5}$
$13 + \sqrt{5}$
$13 - \sqrt{5}$

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Test Details

Duration

0h 45m

Questions

40 Multiple Choice Questions

Passing Score

N/A% or higher to pass

Attempts

Unlimited attempts allowed

Total Runs

100